lunes, 19 de octubre de 2009

jqGrid con ASP.NET y AJAX

jqGrid, Grid jQuery, jqGrid en ASPNET

jqGrid es una excelente grilla (grid) para mostrar y manipular datos en forma tabular. A mi juicio mucho más elegante y potente que el GridView de ASP.NET.

En este articulo veremos el código de ejemplo de implementación de un jqGrid con ASP.NET. Además de poder ver una demo en acción del Grid para jQuery, podremos descargarnos la solución completa.

Pero comentemos el problema que nos planteamos resolver.

jqGrid - ASP.NET, Ejemplo

Asumamos que tenemos una base de datos con una tabla Person, que contiene los datos de determinadas personas y queremos mostrar dicha información en una pagina web, tal como se muestra en la figura:jqGrid, jqGrid Demo, jqGrid ASP.NET, Grid jQuery, jqGrid en ASPNET

Para ello decidimos usar el componente jqGrid de jQuery, entre otras cosas porque:

  • Es una grilla (grid) vistosa y elegante.
  • Nos proporciona gran funcionalidad en el manejo y manipulación de los datos.
  • Al usar AJAX y JSON hace más amigable la navegación del cliente.
  • Nos permite paginado, ordenación, selección múltiple, contraer todo el grid, etc.

Pero como de costumbre vallamos al código que debemos implementar, y analicémoslo paso a paso.

Nota: Como el código es bastante amplio, al final hemos dejado un enlace donde podrás descargarte la solución demo (de ejemplo) competa, así como un BackUP de la base de datos SQL.

jqGrid – ASP.NET - HTML

1. Veamos el código del fichero jqGridEjemplo.aspx y después lo comentaremos:

<%@ Page Language="C#" AutoEventWireup="true"  CodeFile="JqGridEjemplo.aspx.cs" Inherits="JqGridEjemplo" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
  <head runat="server">
    <title>JQGrid con JSON Ejemplo Básico</title>
    <link type="text/css" rel="stylesheet"
          href="css/cupertino/jquery-ui- 1.7.2.custom.css" />
    <link type="text/css" rel="stylesheet"
          href="css/ui.jqgrid.css" />
   
    <script type="text/javascript" src="js/jquery-1.3.2.min.js" ></script>
    <script type="text/javascript"
            src="js/jquery-ui-1.7.2.custom.min.js" ></script> 
    <script type="text/javascript" src="js/grid.locale-sp.js" ></script>   
    <script type="text/javascript" src="js/jquery.jqGrid.min.js" ></script>
    <script type="text/javascript" src="js/grid.base.js" ></script>
    <script type="text/javascript" src="js/grid.common.js" ></script>
    <script type="text/javascript" src="js/grid.formedit.js" ></script>
    <script type="text/javascript" src="js/jquery.fmatter.js" ></script>
    <script type="text/javascript" src="js/json2.js" ></script>
   
    <script type = "text/javascript"> 
      jQuery(document).ready(function()
      {
        $("#grid").jqGrid(
        {
            datatype: function()
            {
              $.ajax(
                {
                  url: "jqGridEjemplo.aspx/GetPersons", //PageMethod
                   
                    data:
                     "{'pPageSize':'" + $('#grid').getGridParam("rowNum") +
                     "','pCurrentPage':'" + $('#grid').getGridParam("page") +
                     "','pSortColumn':'" + $('#grid').getGridParam("sortname") +
                     "','pSortOrder':'" + $('#grid').getGridParam("sortorder")
                       + "'}", //Parametros de entrada del PageMethod
                   
                    dataType: "json",
                    type: "post",
                    contentType: "application/json; charset=utf-8",
                    complete: function(jsondata, stat)
                    {
                      if (stat == "success")
                        jQuery("#grid")[0].addJSONData(JSON.parse
                              (jsondata.responseText).d);
                      else
                        alert(JSON.parse(jsondata.responseText).Message);
                    }
                });
            },
            jsonReader : //jsonReader –> JQGridJSonResponse data.
            {
                root: "Items",
                page: "CurrentPage",
                total: "PageCount",
                records: "RecordCount",
                repeatitems: true,
                cell: "Row",
                id: "ID"
            },
            colModel: //Columns
            [
                { index: 'Name', width: 200, align: 'Left',
                  label: 'Nombre' },               
                { index: 'LastName', width: 300, align: 'Left',
                  label: 'Apellidos' },
                { index: 'BirthDate', width: 200, align: 'Center',
                  label: 'Fecha Nacimiento' },
                { index: 'Weight', width: 100, align: 'center',
                  label: 'Peso (Kg)' }
            ],
            pager: "#pager", //Pager.
            loadtext: 'Cargando datos...',
            recordtext: "{0} - {1} de {2} elementos",
            emptyrecords: 'No hay resultados',
            pgtext : 'Pág: {0} de {1}', //Paging input control text format.
            rowNum: "10", // PageSize.
            rowList: [10,20,30], //Variable PageSize DropDownList.
            viewrecords: true, //Show the RecordCount in the pager.
            multiselect: true,
            sortname: "Name", //Default SortColumn
            sortorder: "asc", //Default SortOrder.
            width: "760",
            height: "230",
            caption: "Personas"
        }).navGrid("#pager", {edit:false, add:false, search:false,
                              del:false});      
      }); 
    </script>
   
  </head>
  <body>
    <table id="grid"></table>
    <div id="pager"></div>
  </body>
</html>

En el código anterior, hemos definido el jqGrid, o sea, la tabla de datos de personas.

Dentro de la etiqueta body encontraras solo 2 elementos; table (grid) que será donde se pintaran los valores de las personas en formato tabular, y la etiqueta div (pager) que será donde aparecerán los datos que encontramos en el pie de la tabla (actualizar, paginación e información general).

En el head encontramos 2 hojas de estilos y los javascript necesarios para dotar al grid de la funcionalidad necesaria, pero por esto no nos preocuparemos ahora, más adelante les indicaremos donde nos podemos descargar estos ficheros.

En el head encontramos también la función $("#grid").jqGrid() que es la encargada de configurar todo el comportamiento del jqGrid o grilla. Dentro de esta función definiremos las propiedades, métodos y eventos, en nuestro ejemplo hemos definido algunas funciones que son muy intuitivas y generales. Una  de estas propiedades es datatype, a esta le asociaremos la función de la llamada AJAX que nos devolverá la lista de personas a mostrar en formato JSON.

jqGrid – ASP.NET – C#

La carga de los datos a mostrar, se hace de forma parcial vía AJAX, o sea, cada vez que el usuario pagine, ordene o haga cualquier acción que necesite recargar nuevos datos, se llamará a la función $.ajax({ url: "jqGridEjemplo.aspx/GetPersons", data:… en nuestro caso es un WebMethod, también podría ser un WS o WCF, pero veamos ahora el code-behind en C# que invocaremos vía AJAX. Este método recibe 4 parámetros que le pasaremos en el parámetro data que vimos anteriormente (pPageSize, pCurrentPage, pSortColumn, pSortOrder). Veamos el código en C#:

public partial class JqGridEjemplo : Page
{
    protected void Page_Load(object sender, EventArgs e) {}
 
    [WebMethod]
    [ScriptMethod(ResponseFormat = ResponseFormat.Json)]
    public static JQGridJsonResponse GetPersons(int pPageSize,
                   int pCurrentPage, string pSortColumn, string pSortOrder)
    {
        return GetPersonasJSon(pPageSize, pCurrentPage, pSortColumn,
                               pSortOrder);
    }
 
 
    internal static JQGridJsonResponse GetPersonasJSon(int pPageSize,
                    int pPageNumber, string pSortColumn, string pSortOrder)
    {
        SqlConnection sqlCon = new SqlConnection ConfigurationManager.
                  ConnectionStrings["DataConnection"].ConnectionString);
        SqlCommand command = new SqlCommand("GetPersons", sqlCon);
        command.CommandType = CommandType.StoredProcedure;
        command.Parameters.Add("PageSize", SqlDbType.Int).Value = pPageSize;
        command.Parameters.Add("CurrentPage", SqlDbType.Int).Value =
                  pPageNumber;
        command.Parameters.Add("SortColumn", SqlDbType.VarChar, 20).Value =
                  pSortColumn;
        command.Parameters.Add("SortOrder", SqlDbType.VarChar, 4).Value =
                  pSortOrder;
 
        DataSet dataSet = new DataSet();
        SqlDataAdapter dataAdapter = new SqlDataAdapter(command);
        dataAdapter.Fill(dataSet);
 
        var persons = new List<Person>();
        foreach (DataRow row in dataSet.Tables[1].Rows)
        {
            Person person = new Person
            {
                ID = Convert.ToInt32(row["ID"]),
                Name = row["Name"].ToString(),
                LastName = row["LastName"].ToString(),
                BirthDate = Convert.ToDateTime(row["BirthDate"]),
                Weight = Convert.ToSingle(row["Weight"])
            };
            persons.Add(person);
        }
 
        return new JQGridJsonResponse(Convert.ToInt32(dataSet.Tables[0].
                     Rows[0]["PageCount"]), Convert.ToInt32(dataSet.
                     Tables[0].Rows[0]["CurrentPage"]),
                     Convert.ToInt32(dataSet.Tables[0].Rows[0]["RecordCount"]),
                     persons);
    }
}

En el código anterior, vemos la definición del WebMethod GetPersons, el cual devolverá solo los registros o personas que se mostraran en el jqGrid, estos datos serán devueltos en formato JSON. Si analizamos el código en profundidad, veremos que se hace una llamada a un procedimiento almacenado SQL Server, que devolverá 2 conjuntos de datos, uno con el subconjunto de personas a mostrar y otro con el total de registros de la tabla personas. Pero veamos el procedimiento almacenado:

ALTER procedure [dbo].[GetPersons]
 
@PageSize int ,
@CurrentPage int ,
@SortColumn varchar(20),
@SortOrder varchar(4)
 
as
 
declare @RecordCount int
declare @PageCount int
declare @PageIndex int
 
Select @RecordCount = count(ID)
from Person
 
set @PageCount = Ceiling(cast (@RecordCount as float) / cast (@PageSize as float))
 
if (@CurrentPage > @PageCount) set @CurrentPage = @PageCount
 
set @PageIndex = @CurrentPage - 1
 
Select RecordCount = @RecordCount, PageCount = @PageCount, CurrentPage = @CurrentPage
 
declare @Query varchar(300)
 
set @Query =
      'Select ID, Name, LastName, BirthDate, Weight,
       RowNumber = ROW_NUMBER() OVER (ORDER BY ' + @SortColumn + ' ' + @SortOrder + ')
       from Person'
 
set @Query =
      'Select ID, Name, LastName, BirthDate, Weight
       from (' + @Query + ' )as result
       where RowNumber BETWEEN ' + cast(@PageSize * @PageIndex + 1 as varchar(10)) + '
                    AND ' + cast(@PageSize * (@PageIndex + 1) as varchar(10))
 
Exec (@Query)

Y con esto y poco más ya  tenemos implementado nuestro grid de jQuery (jqGrid), una excelente rejilla de datos que no te dejará indiferente.

Descargar la solución completa de ejemplo de jqGrid en ASP.NET C#.

Para ver otros ejemplos de jqGrid en la página oficial, pinche aquí.

Nota: Existe ya desarrollado un componente jqGrid especial para ASP.NET con un modelo de programación API muy similar al usado en nuestros desarrollos ASP.NET cotidianos, pero la licencia de este otro componente está entre $300.00 y $450.00 (demo), por lo que mi consejo es que usen el jqGrid estándar que hemos explicado aquí que es GRAAAATISSSSSS.

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75 comentarios:

  1. Hola

    Me gusto mucho el articulo pero cuando intente descargar la demo, me pide un usuario y password... cual es para poder descargarla?

    Gracias

    ResponderEliminar
  2. Hola IcedGuardian, me alegro que te haya gustado el artículo, ya puedes descargarte la solución completa de jqGrid para ASP.Net. Efectivamente se necesitaba un login para la descarga, pero ya no lo necesitas.

    Espero te sea de utilidad el código de descarga, te recuerdo que es un ejemplo ASP.NET WebForm jqGrid realizado en C#.

    Un salu2, Derbis

    PD: Este mismo artículo lo tengo publicado en este otro blogs http://www.esasp.net/2009/10/jqgrid-con-aspnet-y-ajax.html que estoy potenciando.

    ResponderEliminar
  3. Hola Derbis

    Gracias por tu respuesta, acabo de bajar el ejemplo, lastima que estoy usando VS 2005 y el framework 2.0

    De todas maneras, intentare modificar mi ejemplo y seguir de guia el ejemplo que tu creaste

    Mis ganas de probar jqGrid nace de la necesidad de usar un componente de grilla que sea rapido y me permita trabajar con grandes volumenes de data. Por ahora estaba usando UltraWebGrid de Infragistics, el cual sin ser un mal componente, esta poco documentado, tiene problemas de perfomance, entre algunas otras cosas. He logrado buenos avances con UltraWebGrid pero he llegado a determinado punto en donde se hace critica la usabilidad de esta

    Me dare entonces una vuelta por tu blog, he visto los articulos, estan muy buenos

    Gracias!

    Saludos

    ResponderEliminar
    Respuestas
    1. Hola, de casualidad tienes el ejemplo, si lo tuviera, me lo podría enviar por correo, ya que el link de descarga está malo...se lo agradecería en gran manera

      Eliminar
  4. Excelente articulo, es uno de los mejores que he visto, pero he intentado descargar el código, pero está malo el enlace, si fuera posible habilitar el enlace de descarga, te lo agradecería mucho.

    ResponderEliminar
  5. muy bueno el articulo pero el link de descarga no me funciona me lo podria enviar por correo es janet@otn.vcl.cu mil gracias

    ResponderEliminar
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